I think I have created a pretty accurate formula for calculating how many times your body weight you are pulling down during front lever.
1 / sin(θ)
θ = angle between arm and body during front lever
Alternatively if you can't find θ:
1 / (√(a[sup]2[/sup] - b[sup]2[/sup]) / a)
a = armlength in meters.
b = distance from shoulder (when depressed) to center of mass in meters.
(This)
Example:
my arms are 0,6 m long and
there are 0,4 m from my depressed shoulders to my center of mass
1 / (√(0,6[sup]2[/sup] - 0,4[sup]2[/sup]) / 0,6) = 1,3416407865
When if I could do the front lever I would be pulling down about 1,3 times body weight.
I'm 99% sure that this formular is aplicable to both back lever and planche.
I'm currently in ninth grade, which means I have no formal education in physics (or anything else). So if someone smart could point out potential mistakes, it would be appreciated.
1 / sin(θ)
θ = angle between arm and body during front lever
Alternatively if you can't find θ:
1 / (√(a[sup]2[/sup] - b[sup]2[/sup]) / a)
a = armlength in meters.
b = distance from shoulder (when depressed) to center of mass in meters.
(This)
Example:
my arms are 0,6 m long and
there are 0,4 m from my depressed shoulders to my center of mass
1 / (√(0,6[sup]2[/sup] - 0,4[sup]2[/sup]) / 0,6) = 1,3416407865
When if I could do the front lever I would be pulling down about 1,3 times body weight.
I'm 99% sure that this formular is aplicable to both back lever and planche.
I'm currently in ninth grade, which means I have no formal education in physics (or anything else). So if someone smart could point out potential mistakes, it would be appreciated.